A 10-foot-tall tank uses a transducer that measures the liquid level with a 1-5 VDC signal monitoring the top 8 feet. If the transducer reads 3.5 VDC, how many feet of water are in the tank?

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Multiple Choice

A 10-foot-tall tank uses a transducer that measures the liquid level with a 1-5 VDC signal monitoring the top 8 feet. If the transducer reads 3.5 VDC, how many feet of water are in the tank?

Explanation:
The transducer’s voltage maps linearly to how much of the top 8 feet is filled. Since the tank is 10 feet tall, the bottom of the monitored 8-foot span sits 2 feet above the tank bottom. A 3.5 V reading corresponds to 0.625 of the 8-foot span (because (3.5 − 1) / (5 − 1) = 2.5/4 = 0.625). That means 0.625 × 8 ft = 5 ft of water within the monitored top region. Adding the 2 ft offset from the bottom of the tank gives 7 ft of water in the tank.

The transducer’s voltage maps linearly to how much of the top 8 feet is filled. Since the tank is 10 feet tall, the bottom of the monitored 8-foot span sits 2 feet above the tank bottom. A 3.5 V reading corresponds to 0.625 of the 8-foot span (because (3.5 − 1) / (5 − 1) = 2.5/4 = 0.625). That means 0.625 × 8 ft = 5 ft of water within the monitored top region. Adding the 2 ft offset from the bottom of the tank gives 7 ft of water in the tank.

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