The deadband in a trigger causes which of the following regarding output switching as the input moves around the threshold?

• A. It prevents the output from switching ON and OFF as the input crosses the threshold
• B. It increases switch frequency near the threshold
• C. It inverts the output signal
• D. It makes the output lag behind the input by a fixed amount

Answer: (A)

A deadband creates a small cushion around the switching threshold so that tiny fluctuations near the threshold don’t cause the output to flip on and off. This keeps the output from chattering when the input is around that point, since the signal must move far enough in one direction to cross the margin and change state. In practical terms, the output stays in its current state as the input hovers around threshold, preventing rapid toggling. This is why the description that best fits is that it prevents the output from switching ON and OFF as the input crosses the threshold. It does not inherently increase switch frequency, invert the signal, or introduce a fixed time delay.